Just wondering what everyone preferred to use when replacing, breaking, etc. their chains. Are you using a Kit you found somewhere? What kind of press, breaker, etc are you using?
I'm looking for some new tools and want to hear your reviews.
Not the same quality and im not sure if you can buy parts individual like the RK one...but same design.
MotoKirby
Subject: Re: Chain Tools Wed Aug 24, 2011 8:31 pm
I use the stockton Cycle gear chain tool posted in the other reply. I have had good results with it for the last couple of years. I would recommend it, and cycle gear usually has some coupon or sale going on for this type of stuff.
Arkmage
Subject: Re: Chain Tools Wed Aug 24, 2011 9:17 pm
4" angle grinder, a punch, a vise, and a hammer... nothing special.
Jäger Admin
Subject: Re: Chain Tools Thu Aug 25, 2011 1:52 am
Master link and a small pair of slip joint pliers. They look shockingly like the ones that came in the stock tool kit.
greer
Subject: Re: Chain Tools Thu Aug 25, 2011 5:17 am
A cutting wheel on a Dremel is fast and easy.
Sarah
rc23
Subject: Re: Chain Tools Thu Aug 25, 2011 9:03 am
You'd be amazed how much quicker(and cleaner) it is to actually push the pin through a chain with the correct tool.
Then again the wrx is my first bike with a clip link - everything else I have to have a chain tool so I'm used to it.
I'd get the stockton one from cycle gear if you're on a budget - just my $.02
RLP65202
Subject: Re: Chain Tools Thu Sep 08, 2011 3:59 pm
I have used this on on my street bike and my WRr have had good luck with it. However it has started to bend so I unfortunatly got what I paid for. But for a tool I may never use again anyway it is cheap and works. http://www.harborfreight.com/heavy-duty-chain-breaker-66488.html
IndigoWolf
Subject: Re: Chain Tools Thu Sep 08, 2011 4:33 pm
Here is what I have ... chain breaker Quick and easy.
DragonNester
Subject: Re: Chain Tools Fri Jan 27, 2012 5:35 pm
Motion Pro Chain Breaker & Riveting Tool...works on bigger chains found on sport bikes and some touring bikes, also.